Optimal. Leaf size=196 \[ -\frac{63 b^{5/2} e^2 \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{4 (b d-a e)^{11/2}}+\frac{63 b^2 e^2}{4 \sqrt{d+e x} (b d-a e)^5}+\frac{21 b e^2}{4 (d+e x)^{3/2} (b d-a e)^4}+\frac{63 e^2}{20 (d+e x)^{5/2} (b d-a e)^3}+\frac{9 e}{4 (a+b x) (d+e x)^{5/2} (b d-a e)^2}-\frac{1}{2 (a+b x)^2 (d+e x)^{5/2} (b d-a e)} \]
[Out]
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Rubi [A] time = 0.328268, antiderivative size = 196, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.152 \[ -\frac{63 b^{5/2} e^2 \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{4 (b d-a e)^{11/2}}+\frac{63 b^2 e^2}{4 \sqrt{d+e x} (b d-a e)^5}+\frac{21 b e^2}{4 (d+e x)^{3/2} (b d-a e)^4}+\frac{63 e^2}{20 (d+e x)^{5/2} (b d-a e)^3}+\frac{9 e}{4 (a+b x) (d+e x)^{5/2} (b d-a e)^2}-\frac{1}{2 (a+b x)^2 (d+e x)^{5/2} (b d-a e)} \]
Antiderivative was successfully verified.
[In] Int[(a + b*x)/((d + e*x)^(7/2)*(a^2 + 2*a*b*x + b^2*x^2)^2),x]
[Out]
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Rubi in Sympy [A] time = 94.8701, size = 175, normalized size = 0.89 \[ - \frac{63 b^{\frac{5}{2}} e^{2} \operatorname{atan}{\left (\frac{\sqrt{b} \sqrt{d + e x}}{\sqrt{a e - b d}} \right )}}{4 \left (a e - b d\right )^{\frac{11}{2}}} - \frac{63 b^{2} e^{2}}{4 \sqrt{d + e x} \left (a e - b d\right )^{5}} + \frac{21 b e^{2}}{4 \left (d + e x\right )^{\frac{3}{2}} \left (a e - b d\right )^{4}} - \frac{63 e^{2}}{20 \left (d + e x\right )^{\frac{5}{2}} \left (a e - b d\right )^{3}} + \frac{9 e}{4 \left (a + b x\right ) \left (d + e x\right )^{\frac{5}{2}} \left (a e - b d\right )^{2}} + \frac{1}{2 \left (a + b x\right )^{2} \left (d + e x\right )^{\frac{5}{2}} \left (a e - b d\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((b*x+a)/(e*x+d)**(7/2)/(b**2*x**2+2*a*b*x+a**2)**2,x)
[Out]
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Mathematica [A] time = 0.826211, size = 168, normalized size = 0.86 \[ \frac{\sqrt{d+e x} \left (-\frac{10 b^3 (b d-a e)}{(a+b x)^2}+\frac{75 b^3 e}{a+b x}+\frac{40 b e^2 (b d-a e)}{(d+e x)^2}+\frac{8 e^2 (b d-a e)^2}{(d+e x)^3}+\frac{240 b^2 e^2}{d+e x}\right )}{20 (b d-a e)^5}-\frac{63 b^{5/2} e^2 \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{4 (b d-a e)^{11/2}} \]
Antiderivative was successfully verified.
[In] Integrate[(a + b*x)/((d + e*x)^(7/2)*(a^2 + 2*a*b*x + b^2*x^2)^2),x]
[Out]
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Maple [A] time = 0.03, size = 231, normalized size = 1.2 \[ -{\frac{2\,{e}^{2}}{5\, \left ( ae-bd \right ) ^{3}} \left ( ex+d \right ) ^{-{\frac{5}{2}}}}-12\,{\frac{{b}^{2}{e}^{2}}{ \left ( ae-bd \right ) ^{5}\sqrt{ex+d}}}+2\,{\frac{b{e}^{2}}{ \left ( ae-bd \right ) ^{4} \left ( ex+d \right ) ^{3/2}}}-{\frac{15\,{e}^{2}{b}^{4}}{4\, \left ( ae-bd \right ) ^{5} \left ( bex+ae \right ) ^{2}} \left ( ex+d \right ) ^{{\frac{3}{2}}}}-{\frac{17\,{b}^{3}{e}^{3}a}{4\, \left ( ae-bd \right ) ^{5} \left ( bex+ae \right ) ^{2}}\sqrt{ex+d}}+{\frac{17\,{e}^{2}{b}^{4}d}{4\, \left ( ae-bd \right ) ^{5} \left ( bex+ae \right ) ^{2}}\sqrt{ex+d}}-{\frac{63\,{b}^{3}{e}^{2}}{4\, \left ( ae-bd \right ) ^{5}}\arctan \left ({b\sqrt{ex+d}{\frac{1}{\sqrt{b \left ( ae-bd \right ) }}}} \right ){\frac{1}{\sqrt{b \left ( ae-bd \right ) }}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((b*x+a)/(e*x+d)^(7/2)/(b^2*x^2+2*a*b*x+a^2)^2,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)/((b^2*x^2 + 2*a*b*x + a^2)^2*(e*x + d)^(7/2)),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.345465, size = 1, normalized size = 0.01 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)/((b^2*x^2 + 2*a*b*x + a^2)^2*(e*x + d)^(7/2)),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x+a)/(e*x+d)**(7/2)/(b**2*x**2+2*a*b*x+a**2)**2,x)
[Out]
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GIAC/XCAS [A] time = 0.293623, size = 512, normalized size = 2.61 \[ \frac{63 \, b^{3} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right ) e^{2}}{4 \,{\left (b^{5} d^{5} - 5 \, a b^{4} d^{4} e + 10 \, a^{2} b^{3} d^{3} e^{2} - 10 \, a^{3} b^{2} d^{2} e^{3} + 5 \, a^{4} b d e^{4} - a^{5} e^{5}\right )} \sqrt{-b^{2} d + a b e}} + \frac{15 \,{\left (x e + d\right )}^{\frac{3}{2}} b^{4} e^{2} - 17 \, \sqrt{x e + d} b^{4} d e^{2} + 17 \, \sqrt{x e + d} a b^{3} e^{3}}{4 \,{\left (b^{5} d^{5} - 5 \, a b^{4} d^{4} e + 10 \, a^{2} b^{3} d^{3} e^{2} - 10 \, a^{3} b^{2} d^{2} e^{3} + 5 \, a^{4} b d e^{4} - a^{5} e^{5}\right )}{\left ({\left (x e + d\right )} b - b d + a e\right )}^{2}} + \frac{2 \,{\left (30 \,{\left (x e + d\right )}^{2} b^{2} e^{2} + 5 \,{\left (x e + d\right )} b^{2} d e^{2} + b^{2} d^{2} e^{2} - 5 \,{\left (x e + d\right )} a b e^{3} - 2 \, a b d e^{3} + a^{2} e^{4}\right )}}{5 \,{\left (b^{5} d^{5} - 5 \, a b^{4} d^{4} e + 10 \, a^{2} b^{3} d^{3} e^{2} - 10 \, a^{3} b^{2} d^{2} e^{3} + 5 \, a^{4} b d e^{4} - a^{5} e^{5}\right )}{\left (x e + d\right )}^{\frac{5}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)/((b^2*x^2 + 2*a*b*x + a^2)^2*(e*x + d)^(7/2)),x, algorithm="giac")
[Out]